Matematika ......................​

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[tex] \mathbb \color{aqua} \underbrace{JAWABAN}[/tex]

No. 1

[tex] \bold{ {f}^{ - 1} (x) = \boxed{ \sf \frac{x + 4}{3} }} \\ [/tex]

No. 2

[tex] \bold{ {g}^{ - 1} (x) = \boxed{ \sf \frac{2x - 4}{2} }}[/tex]

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[tex] \mathbb \color{orange} \underbrace{PENYELESAIAN}[/tex]

No. 1

[tex]\underline{ \overline{ \boxed{ \bold{diketahui}}}}[/tex]

  • f(x) = 3x - 4

[tex] \\ \underline{ \overline{ \boxed{ \bold{ditanya}}}}[/tex]

  • [tex] \sf {f}^{ - 1} (x)[/tex]

[tex] \\ \underline{ \overline{ \boxed{ \bold{jawab}}}}[/tex]

=> misalkan f(x) = y :

[tex] \sf y = 3x - 4 \\ \sf 3x = y + 4~~~~ \\ \sf x = \frac{y + 4}{3} ~[/tex]

[tex] \sf {f}^{ - 1} (x) = \boxed{ \sf \frac{x + 4}{3} }[/tex]

[tex] \\ [/tex]

No. 2

[tex]\underline{ \overline{ \boxed{ \bold{diketahui}}}}[/tex]

  • [tex] \sf g(x) = \frac{2x + 4}{2} [/tex]

[tex] \\ \underline{ \overline{ \boxed{ \bold{ditanya}}}}[/tex]

  • [tex] \sf {g}^{ - 1} (x)[/tex]

[tex] \\ \underline{ \overline{ \boxed{ \bold{jawab}}}}[/tex]

=> misalkan g(x) = y :

[tex] \sf y = \frac{2x + 4}{2}~ \\ \sf y(2) = 2x + 4 ~~~~~~~\\ \sf 2y = 2x + 4 ~~~~\\ \sf 2x = 2y - 4~~~~ \\ \sf x = \frac{2y - 4}{2} [/tex]

[tex] \sf {g}^{ - 1} (x) = \boxed{ \sf \frac{2x - 4}{2} }[/tex]

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[tex] \mathbb \color{red} \underbrace{KESIMPULAN}[/tex]

Jadi, jawabannya adalah :

No. 1

[tex] \implies \sf {f}^{ - 1} (x) = \boxed{ \sf \frac{x + 4}{3} }[/tex]

No. 2

[tex] \implies \sf {g}^{ - 1} (x) = \boxed{ \sf \frac{2x - 4}{2} }[/tex]

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Jawaban:

Jawaban terlampir no 2 kurang bisa

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